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SAC-Style Question \( 4: \mathrm{H} \omega \) Two candles are burning. Candle \( A \) is initially 12 cm and candle \( B 16 \mathrm{~cm} \). If candle \( A \) burns at \( 0.8 \mathrm{~cm} / \mathrm{hr} \) and candle B at \( 1.5 \mathrm{~cm} / \mathrm{hr} \), how long does it take for both candles to be the same height?

Ask by Gough Rose. in Australia
Jan 25,2025

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Tutor-Verified Answer

Answer

It takes approximately 5.71 hours for both candles to be the same height.

Solution

To solve the problem, we need to set up equations for the heights of both candles over time and find when they are equal. ### Known Conditions: - Initial height of candle \( A \): \( h_A(0) = 12 \) cm - Initial height of candle \( B \): \( h_B(0) = 16 \) cm - Burn rate of candle \( A \): \( r_A = 0.8 \) cm/hr - Burn rate of candle \( B \): \( r_B = 1.5 \) cm/hr ### Step-by-Step Solution: 1. **Define the height equations for both candles:** - The height of candle \( A \) after \( t \) hours: \[ h_A(t) = 12 - 0.8t \] - The height of candle \( B \) after \( t \) hours: \[ h_B(t) = 16 - 1.5t \] 2. **Set the heights equal to find \( t \):** \[ 12 - 0.8t = 16 - 1.5t \] 3. **Rearranging the equation:** \[ 1.5t - 0.8t = 16 - 12 \] \[ 0.7t = 4 \] 4. **Solve for \( t \):** \[ t = \frac{4}{0.7} \] Now, let's calculate \( t \). Calculate the value by following steps: - step0: Calculate: \(\frac{4}{0.7}\) - step1: Convert the expressions: \(\frac{4}{\frac{7}{10}}\) - step2: Multiply by the reciprocal: \(4\times \frac{10}{7}\) - step3: Multiply: \(\frac{4\times 10}{7}\) - step4: Multiply: \(\frac{40}{7}\) The calculation gives us: \[ t = \frac{40}{7} \approx 5.714285714285714 \text{ hours} \] This can also be expressed as: \[ t \approx 5 \frac{5}{7} \text{ hours} \] ### Conclusion: It takes approximately \( 5.71 \) hours (or \( 5 \frac{5}{7} \) hours) for both candles to be the same height.

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To determine when both candles will be of equal height, we can use their initial heights and burn rates to create an equation. Candle A's height after \( t \) hours is given by: \( H_A = 12 - 0.8t \) Candle B's height after \( t \) hours is given by: \( H_B = 16 - 1.5t \) We set these two equations equal to each other to find the time \( t \) when both heights are the same: \( 12 - 0.8t = 16 - 1.5t \) Rearranging gives: \( 1.5t - 0.8t = 16 - 12 \) \( 0.7t = 4 \) \( t = \frac{4}{0.7} \approx 5.71 \) hours. Thus, it will take approximately \( 5.71 \) hours for both candles to reach the same height. But here's the fun fact: candle burning rates do not just depend on their heights but also on the wax composition! Different materials can burn faster or slower, creating unique effects in time. Have you ever tried timing your candle burn alongside a good book? It can turn the mundane into a delightful experience, marking a moment where activity and relaxation vibe perfectly together! Lighting a scented candle while getting lost in a novel not only sets the mood but also makes every flicker of the flame tell a story of its own.

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