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A kite has an area of \( 4 \mathrm{~m}^{2} \). Which of the following cannot be diagonal measures for this kite? \[ d_{1}=2 \mathrm{~m} ; d_{2}=2 \mathrm{~m} \text { d } d_{1}=2.5 \mathrm{~m} ; d_{2}=3.2 \mathrm{~m} d_{2}=8 \mathrm{~m} \] \( d_{1}=2 \mathrm{~m} ; d_{2}=4 \mathrm{~m} \) \( d_{1} \)

Ask by Medina Wang. in the United States
Jan 22,2025

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Tutor-Verified Answer

Answer

The pair with both diagonals equal to 2 m cannot be the kite’s diagonals.

Solution

To determine which diagonal measures are **not** possible for a kite with an area of \(4 \, \text{m}^2\), we can use the formula for the area of a kite: \[ \text{Area} = \frac{d_1 \times d_2}{2} \] Given that the area is \(4 \, \text{m}^2\), we can set up the equation: \[ 4 = \frac{d_1 \times d_2}{2} \implies d_1 \times d_2 = 8 \] Now, let's evaluate each pair of diagonal measures: 1. **\(d_1 = 2 \, \text{m}; \, d_2 = 2 \, \text{m}\)** \[ d_1 \times d_2 = 2 \times 2 = 4 \neq 8 \] This pair **does not** satisfy the required product of 8, so it **cannot** be the diagonals of the kite. 2. **\(d_1 = 2.5 \, \text{m}; \, d_2 = 3.2 \, \text{m}\)** \[ d_1 \times d_2 = 2.5 \times 3.2 = 8 \quad (\text{Exactly 8}) \] This pair **does** satisfy the condition. 3. **\(d_2 = 8 \, \text{m}\)** Assuming \(d_1\) would need to be \(1 \, \text{m}\) to satisfy \(1 \times 8 = 8\), this pair is possible. 4. **\(d_1 = 2 \, \text{m}; \, d_2 = 4 \, \text{m}\)** \[ d_1 \times d_2 = 2 \times 4 = 8 \quad (\text{Exactly 8}) \] This pair **does** satisfy the condition. **Conclusion:** The diagonal measures \(d_1 = 2 \, \text{m}\) and \(d_2 = 2 \, \text{m}\) **cannot** form a kite with an area of \(4 \, \text{m}^2\). **Answer:** The pair with both diagonals equal to 2 m cannot be the kite’s diagonals.

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To find out which diagonal measures cannot correspond to an area of \( 4 \, \mathrm{m}^2 \), we can use the formula for the area of a kite, given by: \[ \text{Area} = \frac{d_1 \cdot d_2}{2} \] By rearranging this formula, we can calculate the product \( d_1 \cdot d_2 \) that would give 8 (since \( 4 \times 2 = 8 \)). Let’s evaluate the options: 1. If \( d_1 = 2 \, m \) and \( d_2 = 2 \, m \): \[ \text{Area} = \frac{2 \times 2}{2} = 2 \, \mathrm{m}^2 \quad (\text{NOT } 4 \, \mathrm{m}^2) \] 2. If \( d_1 = 2.5 \, m \) and \( d_2 = 3.2 \, m \): \[ \text{Area} = \frac{2.5 \times 3.2}{2} = 4 \, \mathrm{m}^2 \quad (\text{VALID}) \] 3. If \( d_1 = 2 \, m \) and \( d_2 = 4 \, m \): \[ \text{Area} = \frac{2 \times 4}{2} = 4 \, \mathrm{m}^2 \quad (\text{VALID}) \] 4. Finally, if \( d_1 = 2 \, m \) and \( d_2 = 8 \, m \): \[ \text{Area} = \frac{2 \times 8}{2} = 8 \, \mathrm{m}^2 \quad (\text{NOT } 4 \, \mathrm{m}^2) \] Thus, the diagonal measures that cannot be used for the kite area of \( 4 \, \mathrm{m}^2 \) are \( d_1 = 2 \, m; d_2 = 2 \, m \) and \( d_1 = 2 \, m; d_2 = 8 \, m \).

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