OPEN MIDDLE - Perfect Squares Slrections: Using the digits 1-9, at most one time each, to fill expression evaluate to a perfect square number. \[ 18 \times \square \times 2 \]
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To solve the expression \( 18 \times \square \times 2 \) such that it evaluates to a perfect square using the digits 1-9 only once, let's first simplify the expression to \( 36 \times \square \). This means we need \( 36 \times \square \) to equal a perfect square. Since \( 36 = 6^2 \), we need \( \square \) to be such that \( 36 \times \square = k^2 \) for some integer \( k \). Hence, \( \square \) must also contain factors that contribute to the squarity. We can try various numbers from 1-9 to see if the product with 36 yields a perfect square. Here’s a fun check: if we pick \( \square = 1 \), we get \( 36 \times 1 = 36\), which is \( 6^2\), a perfect square! Using that logic, our digits used are 1, 2, and 8 (for 18). So, one suitable solution could be filling in the blanks as \( 1 \): \[ 18 \times 1 \times 2 = 36 \] Now you have a perfect square! Keep exploring with other digits to find different combinations; who doesn’t love a good perfect square hunt?