Question 10 (1 point) (04.03 MC) Point \( A \) is located at \( (0,4) \), and point \( B \) is located at \( (-2,-3) \). Find the \( x \) value for the point that is \( \frac{1}{4} \) the distance from point \( A \) to point \( \begin{array}{ll}\text { a } & -1.5\end{array} \) b -2 c \( \quad \mathbf{- 0 . 5} \) d \( \quad-1 \)

When finding a point along a line between two coordinates, you can calculate the total distance, then divide it as required. The distance from \( A(0,4) \) to \( B(-2,-3) \) can be calculated using the distance formula. However, since we only need the x-coordinate, we can calculate the x-component separately. The change in x from \( A \) to \( B \) is \( -2 - 0 = -2 \). Since we want to find a point that is \( \frac{1}{4} \) of the distance from \( A \) toward \( B \), we take \( \frac{1}{4} \) of \( -2 \), which is \( -0.5 \). Add this to the x-coordinate of point \( A \) (which is 0): \( 0 + (-0.5) = -0.5 \). So the x value for the required point is \( -0.5 \). The answer is option c: \( -0.5 \).