\( \begin{array}{ll}\square \text { 2. Given the equation of the line, choose the slope of a perpendicular line: } \\ \begin{array}{ll}\text { 1. } y=-\frac{1}{2} x-1 & \text { a. }-\frac{1}{2} \\ \text { 2. } y=2 x+3 & \text { b. } \frac{1}{2} \\ \text { 3. } y=\frac{1}{2} x+4 & \text { c. }-2\end{array} \\ \text { 4. } y=-2 x-1 & \text { d. } 2\end{array} \)

To find the slope of a line that is perpendicular to a given line, you'll want to take the negative reciprocal of the original line's slope. For instance, if a line has a slope of \( m \), a line perpendicular to it will have a slope of \( -\frac{1}{m} \). Therefore, for the equation \( y = -\frac{1}{2}x - 1 \), the slope is \( -\frac{1}{2} \), making a perpendicular slope \( 2 \). So, you would select option d, \( 2 \). For the line \( y = 2x + 3 \), the slope is \( 2 \). The negative reciprocal of this slope would be \( -\frac{1}{2} \), pointing to the fact that if you're ever in doubt, just flip that fraction and change the sign! Keep an eye out for those slope signs; they can turn your math world upside down!