LMNP is a rectangle. Find the value of \( x \) and the length of each diagonal. \( L N=12 x-6 \) and \( M P=7 x+7 \) \( x=\frac{13}{5} \) (Simplify your answer.) \( L N=\frac{126}{5} \) (Simplify your answer.) MP \( =\square \) (Simplify your answer.)
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First, let's substitute the value of \( x \) into the expressions for the lengths of the sides: 1. For \( LN \): \[ LN = 12x - 6 = 12\left(\frac{13}{5}\right) - 6 = \frac{156}{5} - \frac{30}{5} = \frac{126}{5} \] 2. For \( MP \): \[ MP = 7x + 7 = 7\left(\frac{13}{5}\right) + 7 = \frac{91}{5} + \frac{35}{5} = \frac{126}{5} \] Now, both lengths \( LN \) and \( MP \) are equal, which is expected in a rectangle. To find the length of the diagonal \( d \) of the rectangle \( LMNP \), we can use the Pythagorean theorem: \[ d = \sqrt{LN^2 + MP^2} \] Since \( LN = MP = \frac{126}{5} \): \[ d = \sqrt{\left(\frac{126}{5}\right)^2 + \left(\frac{126}{5}\right)^2} = \sqrt{2\left(\frac{126^2}{25}\right)} = \sqrt{\frac{2 \times 15876}{25}} = \sqrt{\frac{31752}{25}} = \frac{\sqrt{31752}}{5} \] Now, simplifying \( \sqrt{31752} \): \[ \sqrt{31752} = 6\sqrt{882} = 6 \times 21 \sqrt{2} = 126 \sqrt{2} \] Thus, \[ d = \frac{126 \sqrt{2}}{5} \] So, the answers are: \( x = \frac{13}{5} \), \( LN = \frac{126}{5} \), \( MP = \frac{126}{5} \), and the length of the diagonal \( d = \frac{126 \sqrt{2}}{5} \).