Factor each expression: \( \begin{array}{l}x^{2}-9 x+14=\square \\ x^{2}-3 x-10=\square \\ x^{2}+1 x-6=\square\end{array} \)

For the expression \(x^{2} - 9x + 14\), we look for two numbers that multiply to \(14\) and add up to \(-9\). Those numbers are \(-7\) and \(-2\). Therefore, we can factor it as \((x - 7)(x - 2)\). For the expression \(x^{2} - 3x - 10\), we need two numbers that multiply to \(-10\) and add to \(-3\). The numbers \(-5\) and \(2\) fit this requirement, so we can factor it as \((x - 5)(x + 2)\). Finally, in \(x^{2} + 1x - 6\), we look for two numbers that multiply to \(-6\) and add to \(1\). The numbers \(3\) and \(-2\) work here, giving us the factorization \((x + 3)(x - 2)\). To summarize: 1. \(x^{2} - 9x + 14 = (x - 7)(x - 2)\) 2. \(x^{2} - 3x - 10 = (x - 5)(x + 2)\) 3. \(x^{2} + 1x - 6 = (x + 3)(x - 2)\)