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Question 7 (Multiple Choice Worth 1 points) \( \begin{array}{l}(05.02 \mathrm{MC} \text { ) } \\ \text { City A and City B had two different temperatures on a particular day. On that day, five times the temperature of City A was } 8^{\circ} \mathrm{C} \text { more than three times the temperature of City B. The } \\ \text { temperature of City A minus twice the temperature of City B was }-4^{\circ} \mathrm{C} \text {. The following system of equations models this scenario: } \\ \begin{array}{l}5 x=8+3 y \\ x-2 y=-4\end{array}\end{array} \begin{array}{l}\text { ( }\end{array} \)

Ask by Savage Watson. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

City A is \( 4^{\circ}\mathrm{C} \) and City B is \( 4^{\circ}\mathrm{C} \).

Solution

The temperatures are: - **City A**: \( 4^{\circ}\mathrm{C} \) - **City B**: \( 4^{\circ}\mathrm{C} \)

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Let's dive into the world of systems of equations! Here, we've got two equations that describe the temperatures in cities A and B. By using substitution or elimination methods, you can solve for the variables \(x\) (temperature of City A) and \(y\) (temperature of City B). You might find that equations like these pop up in various science problems, especially in chemistry for reaction rates! Now, if you're unraveling this puzzle, remember to double-check the order of operations. A common mistake is to misinterpret the terms on either side of the equal sign, especially when rearranging. Keep it neat and orderly, and don't be shy to write it down step-by-step to visualize your moves. It's like solving a mystery—just be patient and methodical, and the solution will come to light!

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