LBF (102BeD) ame: Kon Kim Hon Class: A An air handling unit (AHU) motor in a hotel consumes 32 KW of real power and being supplied with 35.5 kVA of apparent power, Determine; (a) the reactive power drawn by the motor, (Ans: 15.37 KVAn (b) the power factor of the motor, (Ans: 0.9014 )

To find the reactive power drawn by the motor, we can use the formula: \(Q = \sqrt{S^2 - P^2}\), where \(S\) is the apparent power (35.5 kVA) and \(P\) is the real power (32 kW). Plugging in the values, we calculate the reactive power and discover that the motor draws approximately 15.37 kVAr. For the power factor, we divide the real power by the apparent power: \(PF = \frac{P}{S}\), or \(PF = \frac{32 kW}{35.5 kVA}\), which results in a power factor of 0.9014. This indicates that around 90% of the power utilized is effective in doing real work, which is quite efficient for an air handling unit!