What is the frequency of a blue light with a wavelength of \( 4.83 \times 10^{-7} \mathrm{~m} \) ? Give your answer in proper scientific notation. \[ [?] \times 10^{[?]} \mathrm{Hz} \] \( \quad \mathrm{c}=3.0 \times 10^{8} \mathrm{~m} / \mathrm{s} \) Enter the coeficient in the green box and the exponent in the yellow box.

To find the frequency of light, we can use the formula: \[ f = \frac{c}{\lambda} \] where: - \( f \) is the frequency, - \( c \) is the speed of light, and - \( \lambda \) is the wavelength. Given: - \( c = 3.0 \times 10^{8} \, \mathrm{m/s} \) - \( \lambda = 4.83 \times 10^{-7} \, \mathrm{m} \) Now, we can substitute the values into the formula: \[ f = \frac{3.0 \times 10^{8}}{4.83 \times 10^{-7}} \] Let's calculate this step by step. 1. Calculate the coefficient: \[ \frac{3.0}{4.83} \approx 0.6205 \] 2. Calculate the exponent: \[ 10^{8 - (-7)} = 10^{8 + 7} = 10^{15} \] Now, combine the coefficient and the exponent: \[ f \approx 0.6205 \times 10^{15} \] To express this in proper scientific notation, we need to adjust the coefficient to be between 1 and 10: \[ 0.6205 \times 10^{15} = 6.205 \times 10^{14} \] Thus, the frequency of the blue light is: \[ f \approx 6.205 \times 10^{14} \, \mathrm{Hz} \] Now, we can fill in the green and yellow boxes: - Coefficient: \( 6.205 \) - Exponent: \( 14 \) So the final answer is: \[ [6.205] \times 10^{[14]} \, \mathrm{Hz} \]