Question
2. \( \sqrt{48}-\sqrt{12}+\sqrt{27} \)
Ask by Mckenzie Adkins. in the Philippines
Jan 21,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( 5\sqrt{3} \)
Solution
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Bonus Knowledge
To simplify \( \sqrt{48}-\sqrt{12}+\sqrt{27} \), we can break down each square root into its simplest form. First, \( \sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt{3} \). Next, \( \sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3} \). Lastly, \( \sqrt{27} = \sqrt{9 \cdot 3} = 3\sqrt{3} \). Now we can substitute these back: \[ 4\sqrt{3} - 2\sqrt{3} + 3\sqrt{3} \] Combining like terms gives us: \[ (4 - 2 + 3)\sqrt{3} = 5\sqrt{3} \] Thus, the final answer is \( 5\sqrt{3} \).