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Solve the equation \[ \frac{1}{7}(6 t-4)=\frac{1}{14}(t+4) \]

Ask by Wood Savage. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

\( t = \frac{12}{11} \)

Solution

To solve the equation: \[ \frac{1}{7}(6t - 4) = \frac{1}{14}(t + 4) \] follow these steps: ### Step 1: Eliminate the Fractions To simplify the equation, multiply both sides by the least common multiple (LCM) of the denominators 7 and 14. The LCM of 7 and 14 is **14**. \[ 14 \times \frac{1}{7}(6t - 4) = 14 \times \frac{1}{14}(t + 4) \] ### Step 2: Simplify Both Sides \[ 2 \times (6t - 4) = 1 \times (t + 4) \] \[ 2(6t - 4) = t + 4 \] \[ 12t - 8 = t + 4 \] ### Step 3: Solve for \( t \) 1. **Subtract \( t \) from both sides:** \[ 12t - t - 8 = t - t + 4 \] \[ 11t - 8 = 4 \] 2. **Add 8 to both sides:** \[ 11t - 8 + 8 = 4 + 8 \] \[ 11t = 12 \] 3. **Divide both sides by 11:** \[ t = \frac{12}{11} \] ### Step 4: Simplify the Fraction (Optional) \[ t = 1 \frac{1}{11} \quad \text{or approximately} \quad t \approx 1.0909 \] ### **Final Answer** \[ t = \frac{12}{11} \]

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To solve the equation \[ \frac{1}{7}(6t-4) = \frac{1}{14}(t+4), \] we start by eliminating the fractions. We can do this by finding a common denominator. The least common multiple of 7 and 14 is 14. Thus, we will multiply both sides of the equation by 14: \[ 14 \cdot \frac{1}{7}(6t-4) = 14 \cdot \frac{1}{14}(t+4). \] This simplifies to: \[ 2(6t-4) = t+4. \] Now, distribute the 2 on the left side: \[ 12t - 8 = t + 4. \] Next, we combine like terms. Subtract \(t\) from both sides: \[ 12t - t - 8 = 4. \] This simplifies to: \[ 11t - 8 = 4. \] Now, we add 8 to both sides: \[ 11t = 4 + 8, \] which gives us: \[ 11t = 12. \] Finally, divide both sides by 11 to isolate \(t\): \[ t = \frac{12}{11}. \] Thus, the solution to the equation is \[ \boxed{\frac{12}{11}}. \]

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