Question
5. Anvar va Salimda jami 17 ta yong'oq bor. Anvarda Salimga qaraganda 3 ta kamroq yong'oq bor. Salimda nechta yong'oq bor? \( \begin{array}{llll}\text { A) } 7 \text { ta } & \text { B) } 8 \text { ta } & \text { C) } 9 \text { ta } & \text { D) } 10 \text { ta }\end{array} \)
Ask by Welch Stanley. in Uzbekistan
Jan 22,2025
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Салиму принадлежит 10 орехов.
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Deylik, Anvarda \( x \) ta yong'oq bor. Shunda Salimda \( x + 3 \) ta yong'oq bo'ladi. Jami yong'oq 17 ta bo'lganligi uchun quyidagi tenglama hosil qilamiz: \[ x + (x + 3) = 17 \] Bu yerda \( 2x + 3 = 17 \) ga teng. Endi 3-ni ikkala tomondan chiqaramiz: \[ 2x = 17 - 3 \] \[ 2x = 14 \] Ikkiga bo'lganda: \[ x = 7 \] Shunday qilib, Anvarda 7 ta yong'oq bor, demak Salimda \( 7 + 3 = 10 \) ta yong'oq bor. To'g'ri javob \( D) 10 \) ta.