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Considere a função de acumulação \( A(t) = 5t^2 + 3t \). Calcule o valor de \( A(4) - A(1) \) para encontrar a quantidade acumulada entre os tempos t=1 e t=4.

Ask by Li Pritchard. in Brazil
Jan 24,2025

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A quantidade acumulada entre \( t = 1 \) e \( t = 4 \) é **84** unidades.

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The Deep Dive

Para calcular \( A(4) - A(1) \), primeiro precisamos determinar \( A(4) \) e \( A(1) \): 1. Calcule \( A(4) \): \[ A(4) = 5(4)^2 + 3(4) = 5(16) + 12 = 80 + 12 = 92 \] 2. Calcule \( A(1) \): \[ A(1) = 5(1)^2 + 3(1) = 5(1) + 3 = 5 + 3 = 8 \] Agora, subtraímos os resultados obtidos: \[ A(4) - A(1) = 92 - 8 = 84 \] Portanto, a quantidade acumulada entre os tempos \( t=1 \) e \( t=4 \) é \( 84 \).

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