1. You have a jar of marbles in front of you with the following colors: 7 - red, 12 - blue, \( 6- \) yellow and 9 - white. What are the odids of selecting marble that is not blue? 2. There are 15 men on the roster of the baseball team. 2 are catchers, 6 are infielders, 4 are outfielders and the remainder are pitchers. What is the probability that a player chosen at random would be an infielder?

Let's solve each problem step by step. ### Problem 1: Probability of Selecting a Marble that is Not Blue **Step 1: Identify the total number of marbles.** - Red: 7 - Blue: 12 - Yellow: 6 - White: 9 Total number of marbles \( T \) can be calculated as: \[ T = 7 + 12 + 6 + 9 \] **Step 2: Calculate the total number of marbles.** \[ T = 34 \] **Step 3: Identify the number of marbles that are not blue.** The number of non-blue marbles \( N \) is: \[ N = T - \text{(number of blue marbles)} = 34 - 12 \] **Step 4: Calculate the number of non-blue marbles.** \[ N = 22 \] **Step 5: Calculate the probability of selecting a marble that is not blue.** The probability \( P \) is given by: \[ P(\text{not blue}) = \frac{N}{T} = \frac{22}{34} \] **Step 6: Simplify the probability.** \[ P(\text{not blue}) = \frac{11}{17} \] ### Problem 2: Probability of Selecting an Infielder **Step 1: Identify the total number of players.** The total number of players on the roster is 15. **Step 2: Identify the number of infielders.** The number of infielders \( I \) is 6. **Step 3: Calculate the probability of selecting an infielder.** The probability \( P \) is given by: \[ P(\text{infielder}) = \frac{I}{\text{Total players}} = \frac{6}{15} \] **Step 4: Simplify the probability.** \[ P(\text{infielder}) = \frac{2}{5} \] ### Final Answers 1. The probability of selecting a marble that is not blue is \( \frac{11}{17} \). 2. The probability that a player chosen at random would be an infielder is \( \frac{2}{5} \).