Question
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A game involves tossing two coins. A player wins \( \$ 1.00 \) if both tosses result in heads. What should you pay to play this game in order to make fair game? Explain your reasoning. You should pay \( \$ \square \) to play this game in order to make it a fair game.

Ask by Carlson Nunez. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

You should pay \$0.25 to play the game to make it fair.

Solution

To determine a fair price to play the game, we need to calculate the **expected value** of the game. A fair game means that the cost to play equals the expected winnings, ensuring neither the player nor the organizer has an advantage over time. **Here's how to calculate it:** 1. **Determine the possible outcomes when tossing two coins:** - **HH (Heads-Heads):** Player wins \$1.00 - **HT (Heads-Tails):** Player wins \$0 - **TH (Tails-Heads):** Player wins \$0 - **TT (Tails-Tails):** Player wins \$0 2. **Calculate the probability of each outcome:** - There are 4 possible outcomes, each equally likely. - **Probability of HH:** \( \frac{1}{4} \) - **Probability of HT:** \( \frac{1}{4} \) - **Probability of TH:** \( \frac{1}{4} \) - **Probability of TT:** \( \frac{1}{4} \) 3. **Determine the expected winnings:** \[ \text{Expected Winnings} = \left(\frac{1}{4} \times \$1.00\right) + \left(\frac{3}{4} \times \$0\right) = \$0.25 \] 4. **Set the cost equal to the expected winnings for a fair game:** \[ \text{Fair Price to Play} = \$0.25 \] **Conclusion:** You should pay **\$0.25** to play this game in order to make it a fair game.

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To determine a fair price for playing the game, we first need to calculate the probability of winning. When tossing two coins, there are four possible outcomes: HH (Heads-Heads), HT (Heads-Tails), TH (Tails-Heads), and TT (Tails-Tails). Only one of these outcomes (HH) results in a win. Therefore, the probability of winning is \( \frac{1}{4} \). If the player wins \( \$1.00 \) when both coins show heads, the expected value of the game can be calculated as: \[ \text{Expected Value} = (\text{Probability of Winning} \times \text{Winnings}) + (\text{Probability of Losing} \times \text{Loss}) \] Substituting in the values, we get: \[ \text{Expected Value} = \left(\frac{1}{4} \times 1\right) + \left(\frac{3}{4} \times -x\right) \] For the game to be fair, the expected value should equal zero. Thus, you can set up the equation and solve for \( x \): \[ 0 = \frac{1}{4} - \frac{3x}{4} \] \[ \frac{3x}{4} = \frac{1}{4} \implies 3x = 1 \implies x = \frac{1}{3} \] To make it a fair game, you should pay \( \$\frac{1}{3} \) to play this game.

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