b. Ball lands on 31 or 00 The probability of the event that the ball lands on 31 or 00 is $$ \frac{1}{20} $$.

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To analyze the probability of the event that the ball lands on 31 or 00, we can break down the problem as follows:

1. **Identify the known conditions:**
   - The event of interest is that the ball lands on either 31 or 00.
   - The probability of this event is given as $$ P(A) = \frac{1}{20} $$.

2. **Understanding the event:**
   - The event consists of two outcomes: landing on 31 and landing on 00.
   - Since these outcomes are mutually exclusive (the ball cannot land on both at the same time), we can express the probability of the event as the sum of the probabilities of each individual outcome.

3. **Expressing the probabilities:**
   - Let $$ P(31) $$ be the probability that the ball lands on 31.
   - Let $$ P(00) $$ be the probability that the ball lands on 00.
   - Therefore, we can write:
     $$
     P(A) = P(31) + P(00)
     $$
   - Given that $$ P(A) = \frac{1}{20} $$, we have:
     $$
     P(31) + P(00) = \frac{1}{20}
     $$

4. **Conclusion:**
   - Without additional information about the individual probabilities $$ P(31) $$ and $$ P(00) $$, we cannot determine their specific values. However, we know that their sum equals $$ \frac{1}{20} $$.

If you have any specific questions or need further calculations regarding this probability, please let me know!
The probability of the ball landing on 31 or 00 is $$ \frac{1}{20} $$.

b. Ball lands on 31 or 00 The probability of the event that the ball lands on 31 or 00 is \( \frac{1}{20} \).

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