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Factor. \[ 5 z^{2}-22 z+8 \] \( \square \)

Ask by Garrett Park. in the United States
Jan 26,2025

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Answer

The factored form of \( 5z^{2} - 22z + 8 \) is \( (5z - 2)(z - 4) \).

Solution

To factor the quadratic expression \( 5z^{2} - 22z + 8 \), follow these steps: 1. **Identify the Coefficients:** - \( a = 5 \) (coefficient of \( z^2 \)) - \( b = -22 \) (coefficient of \( z \)) - \( c = 8 \) (constant term) 2. **Find Two Numbers That Multiply to \( a \times c = 5 \times 8 = 40 \) and Add to \( b = -22 \):** - The numbers are **-2** and **-20** because: - \( (-2) \times (-20) = 40 \) - \( (-2) + (-20) = -22 \) 3. **Rewrite the Middle Term Using These Numbers:** \[ 5z^{2} - 2z - 20z + 8 \] 4. **Factor by Grouping:** \[ (5z^{2} - 2z) + (-20z + 8) = z(5z - 2) - 4(5z - 2) \] 5. **Factor Out the Common Binomial:** \[ (z - 4)(5z - 2) \] **Final Factored Form:** \[ (5z - 2)(z - 4) \]

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The Deep Dive

To factor the quadratic expression \( 5z^2 - 22z + 8 \), we need to look for two numbers that multiply to \( 5 \times 8 = 40 \) and add up to \( -22 \). The numbers \( -20 \) and \( -2 \) do the trick! So, we can rewrite the middle term: \[ 5z^2 - 20z - 2z + 8 \] Now, we group the terms: \[ (5z^2 - 20z) + (-2z + 8) \] Factoring each group gives us: \[ 5z(z - 4) - 2(z - 4) \] Now, we can factor out the common factor \( (z - 4) \): \[ (z - 4)(5z - 2) \] And there you have it! The factored form is \( (z - 4)(5z - 2) \). As a fun fact, factoring quadratics is like solving a puzzle—finding the right numbers to fit the equation! With practice, it becomes second nature. In the grand scheme of math, quadratics often pop up in real-world scenarios, like calculating the trajectory of a thrown ball or optimizing areas in agriculture. Knowing how to factor them can provide insights into these practical situations!

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