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Determine the amplitude, period, and phase shift (if any) of the given function. Graph the function. \( y=\sin x+7 \) What is the amplitude of \( y=\sin x+7 \) ? (Simplify your answer. Type an exact answer, using \( \pi \) as needed.)

Ask by Dawson Pollard. in the United States
Dec 08,2024

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Answer

Amplitude: 1, Period: \( 2\pi \), Phase Shift: 0

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Beyond the Answer

The amplitude of the function \( y = \sin x + 7 \) is determined by the coefficient in front of the sine function. Since there is no coefficient changing the sine function from its standard form \( y = \sin x \), the amplitude remains 1. The vertical shift of +7 means the entire sine wave moves up by 7 units, but it does not affect the amplitude. The period of the sine function is \( 2\pi \), and there is no phase shift since there is no horizontal shift in the argument of the sine. In summary, the amplitude is 1, the period is \( 2\pi \), and there is no phase shift, just a vertical shift of 7 units. Now, graphing this function would show a standard sine wave oscillating between 6 and 8 on the y-axis, with the midline at \( y = 7 \).

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