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(a) In a certain board game, players spin a spinner to determine how many spaces they advance. The odds in favor of advancing five spaces are \( \frac{5}{14} \). Find the probability of advancing five spaces. (b) Tom has a box of candies with different flavors. He will randomly choose one piece of candy. The probability that he chooses a strawberry-flavored piece is \( \frac{6}{11} \), What are the odds against him choosing a strawberry-flavored piece? (

Ask by Lewis Bright. in the United States
Jan 06,2025

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**Problem (a):** - Probability of advancing five spaces: \( \frac{5}{19} \). **Problem (b):** - Odds against choosing a strawberry-flavored piece: \( 5:6 \).

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To find the probability of advancing five spaces, we use the odds in favor, which are given as \( \frac{5}{14} \). The probability is calculated using the formula \( P = \frac{\text{Odds in favor}}{\text{Odds in favor} + \text{Odds against}} \). Here, the odds against are \( 14 \) (the total outcome) minus \( 5 \) (the favorable outcome), equating to \( 9 \). Thus, the probability of advancing five spaces is \( P = \frac{5}{5 + 9} = \frac{5}{14} \). Now, regarding the odds against Tom choosing a strawberry-flavored piece of candy, if the probability of choosing one is \( \frac{6}{11} \), then the probability of not choosing it (the odds against) equals \( 1 - \frac{6}{11} = \frac{5}{11} \). To convert this to odds against: Odds against = Probability of not choosing \(\frac{5}{11}\) to the Probability of choosing \(\frac{6}{11}\) = \( \frac{5}{6} \). So, the odds against him picking strawberry are \( 5:6 \).

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