What is the domain of the following function? \( y=\sqrt{x+3} \) Answer Attempt 1 out of 2 \( \begin{array}{ll}{[3, \infty)} & {[-3, \infty)} \\ (\infty, 3] & (\infty,-3]\end{array} \)

To determine the domain of the function \( y = \sqrt{x + 3} \), we need to ensure that the expression inside the square root is non-negative. So, we set up the inequality \( x + 3 \geq 0 \). Solving for \( x \), we find \( x \geq -3 \). Therefore, the domain is \( [-3, \infty) \). Make sure to always check your intervals carefully! One common mistake is to forget that the square root function is only defined for non-negative numbers. When you encounter square roots, just remember that the value under the radical must keep the expression real and defined—so don’t let negative numbers sneak in!