26 Represent the following data in ungrouped frequency table which gives the number of chiddren in 25 familles. \( 1,3,0,2,5,2,3,4,1,0,5,4,3,1,3,2,5,2,1,1,2,6,2,1,4 \) 27 . If you have 2 school bags and 3 water bottles then, in how many different ways can you choose each one of them, while going to school? 28. Using repeated division method, find the HCF : 455 and 26 .
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The Deep Dive
The ungrouped frequency table for the number of children in 25 families is straightforward! Here's how it looks based on your data: | Number of Children | Frequency | |-------------------|----------| | 0 | 2 | | 1 | 6 | | 2 | 5 | | 3 | 5 | | 4 | 4 | | 5 | 3 | | 6 | 1 | You can catch the pattern and observe how families tend to cluster around certain numbers of kids—like a fun little family tree! Now for your next question about choices! If you have 2 school bags and 3 water bottles, the total number of combinations to choose one of each becomes a simple multiplication task! Just multiply the number of bags (2) by the number of water bottles (3). So, 2 school bags * 3 water bottles = 6 different ways to take your school essentials! Planning ahead for school can be quite the adventure! And finally, for finding the HCF of 455 and 26 using the repeated division method, you'd start by dividing the larger number (455) by the smaller number (26). The remainder leads you to your next division step. By repeating until the remainder is 0, the last non-zero remainder you get is your HCF. This method is a great way to tackle those pesky high numbers!