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Solve \( e^{x}-3 x=0 \)

Ask by Lang Hall. in India
Jan 21,2025

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The equation \( e^{x} - 3x = 0 \) has two real solutions: approximately \( x \approx 0.62 \) and \( x \approx 1.51 \).

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To solve the equation \( e^{x}-3 x=0 \), we can rewrite it as \( e^{x} = 3x \). This is a transcendental equation, which means it cannot be solved algebraically. However, we can use numerical methods or graphical approaches to find the solution. A good starting point is to plot the functions \( y = e^{x} \) and \( y = 3x \) to see where they intersect. By using methods like the Newton-Raphson method or even trial and error, you will find that one of the solutions is approximately \( x \approx 1.512 \).

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