much earlier would it have arrived at B? Two men running towards each other at \( 4 \mathrm{~m} / \mathrm{s} \) and \( 6 \mathrm{~m} / \mathrm{s} \), respectively, are one kilometre apart. How long will it tak before they meet?
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To find out how long it will take for the two men to meet, we can first determine their combined speed. One man is running at 4 m/s and the other at 6 m/s. So, their combined speed is: \[ 4 \, \text{m/s} + 6 \, \text{m/s} = 10 \, \text{m/s} \] Next, since they are 1 kilometer apart, we convert that distance into meters: \[ 1 \, \text{km} = 1000 \, \text{m} \] Now we can calculate the time it takes for them to meet using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] \[ \text{Time} = \frac{1000 \, \text{m}}{10 \, \text{m/s}} = 100 \, \text{s} \] Thus, it will take 100 seconds for the two men to meet. Now, let's answer the first part about how much earlier one would arrive at a point B. If you specify the question properly regarding point B, I can help you work that out!