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4. Find the HCF and LCM for th a) 40 and 56

Ask by Morgan Tucker. in South Africa
Jan 23,2025

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Answer

The HCF of 40 and 56 is 8, and the LCM is 280.

Solution

To find the **Highest Common Factor (HCF)** and the **Least Common Multiple (LCM)** of the numbers **40** and **56**, we can use the **Prime Factorization Method**. Here's a step-by-step guide: --- ### **1. Prime Factorization** **a) Prime Factors of 40:** 1. **40 ÷ 2 = 20** 2. **20 ÷ 2 = 10** 3. **10 ÷ 2 = 5** 4. **5 ÷ 5 = 1** So, the prime factors of 40 are: \[ 40 = 2 \times 2 \times 2 \times 5 = 2^3 \times 5 \] **b) Prime Factors of 56:** 1. **56 ÷ 2 = 28** 2. **28 ÷ 2 = 14** 3. **14 ÷ 2 = 7** 4. **7 ÷ 7 = 1** So, the prime factors of 56 are: \[ 56 = 2 \times 2 \times 2 \times 7 = 2^3 \times 7 \] --- ### **2. Finding the HCF (Highest Common Factor)** The **HCF** is the product of the **lowest powers** of all common prime factors. - **Common Prime Factors of 40 and 56:** \( 2^3 \) Therefore: \[ \text{HCF} = 2^3 = 8 \] --- ### **3. Finding the LCM (Least Common Multiple)** The **LCM** is the product of the **highest powers** of all prime factors present in either number. - **Prime Factors to Consider:** \( 2^3 \), \( 5 \), and \( 7 \) Therefore: \[ \text{LCM} = 2^3 \times 5 \times 7 = 8 \times 5 \times 7 = 280 \] *Alternatively, you can use the formula:* \[ \text{LCM}(a, b) = \frac{a \times b}{\text{HCF}(a, b)} \] \[ \text{LCM}(40, 56) = \frac{40 \times 56}{8} = \frac{2240}{8} = 280 \] --- ### **Final Answer:** - **HCF of 40 and 56 is 8** - **LCM of 40 and 56 is 280**

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To find the HCF (Highest Common Factor) of 40 and 56, we start by listing the factors of each number. The factors of 40 are 1, 2, 4, 5, 8, 10, 20, 40, and for 56, they are 1, 2, 4, 7, 8, 14, 28, 56. The largest common factor is 8, so the HCF is 8. Next, we calculate the LCM (Least Common Multiple) using the formula: LCM = (Product of the numbers) / HCF. So, LCM = (40 × 56) / 8 = 280. Therefore, the HCF of 40 and 56 is 8, while the LCM is 280.

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