Consider the arithmetic sequence given by the following values of $$ a_{1} $$ and $$ d $$. $$ a_{1}=8 \quad \text { and } \quad d=5 $$ Determine the ninety-first term of the sequence. $$ a_{91}= $$ Submit Question

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To find the 91st term ($$ a_{91} $$) of an arithmetic sequence, you can use the formula:

$$
a_n = a_1 + (n - 1) \times d
$$

Where:
- $$ a_n $$ is the $$ n $$-th term of the sequence.
- $$ a_1 $$ is the first term.
- $$ d $$ is the common difference.
- $$ n $$ is the term number.

Given:
- $$ a_1 = 8 $$
- $$ d = 5 $$
- $$ n = 91 $$

Plugging the values into the formula:

$$
a_{91} = 8 + (91 - 1) \times 5
$$
$$
a_{91} = 8 + 90 \times 5
$$
$$
a_{91} = 8 + 450
$$
$$
a_{91} = 458
$$

**Answer:** $$ a_{91} = 458 $$
The 91st term of the sequence is 458.

Consider the arithmetic sequence given by the following values of \( a_{1} \) and \( d \). \[ a_{1}=8 \quad \text { and } \quad d=5 \] Determine the ninety-first term of the sequence. \( a_{91}= \) Submit Question

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