Question
Part 2: Linear Relations 1. Given \( C=4.2 n+12 \), solve for \( n \) when \( C=33 \).
Ask by Kelley Curry. in Canada
Jan 22,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( n=5 \)
Solution
Solve the equation \( 4.2n+12=33 \).
Solve the equation by following steps:
- step0: Solve for \(n\):
\(4.2n+12=33\)
- step1: Move the constant to the right side:
\(4.2n=33-12\)
- step2: Subtract the numbers:
\(4.2n=21\)
- step3: Divide both sides:
\(\frac{4.2n}{4.2}=\frac{21}{4.2}\)
- step4: Divide the numbers:
\(n=5\)
The solution to the equation \(4.2n+12=33\) when \(C=33\) is \(n=5\).
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Simplify this solution Bonus Knowledge
To solve for \( n \) in the equation \( C = 4.2n + 12 \) when \( C = 33 \), we start by substituting 33 for \( C \): \[ 33 = 4.2n + 12 \] Next, subtract 12 from both sides: \[ 33 - 12 = 4.2n \] This simplifies to: \[ 21 = 4.2n \] Now, divide both sides by 4.2 to isolate \( n \): \[ n = \frac{21}{4.2} \] Calculating the right side gives: \[ n = 5 \] So, when \( C = 33 \), \( n \) equals 5!
