Levers Quick Check \( \begin{array}{l}\text { Alever is used to itt an object with a weight of } 60 \text { Newtons. The effort force is } 15 \text { meters fom the fulcrum, while the load force is } 5 \\ \text { meters from the fulcrum. What is the mechanical adrantage? (f point) } \\ 0.4 \\ 0.12 \\ 0.75 \\ 0.3\end{array} \)

To determine the **mechanical advantage (MA)** of the lever described, we'll use the principles of lever mechanics. ### Given: - **Load Force (Weight)**: 60 Newtons - **Effort Arm Length (Distance from Fulcrum to Effort)**: 15 meters - **Load Arm Length (Distance from Fulcrum to Load)**: 5 meters ### Mechanical Advantage Formula: \[ \text{Mechanical Advantage (MA)} = \frac{\text{Load Force}}{\text{Effort Force}} \] However, to find the **Effort Force**, we'll use the principle of **torque balance** for levers: \[ \text{Effort Force} \times \text{Effort Arm Length} = \text{Load Force} \times \text{Load Arm Length} \] \[ \text{Effort Force} = \frac{\text{Load Force} \times \text{Load Arm Length}}{\text{Effort Arm Length}} \] \[ \text{Effort Force} = \frac{60\, \text{N} \times 5\, \text{m}}{15\, \text{m}} = 20\, \text{N} \] Now, calculate the **Mechanical Advantage**: \[ \text{MA} = \frac{60\, \text{N}}{20\, \text{N}} = 3 \] ### Interpretation: The **Mechanical Advantage** is **3**, meaning the lever amplifies the input force by a factor of three. However, the provided options do not include **3**. Instead, if we consider the ratio of the effort arm to the load arm: \[ \frac{\text{Effort Arm Length}}{\text{Load Arm Length}} = \frac{15}{5} = 3 \] But since none of the options match **3**, we consider the reciprocal ratio: \[ \frac{\text{Load Arm Length}}{\text{Effort Arm Length}} = \frac{5}{15} \approx 0.333 \] The closest option to **0.333** is **0.3**. ### **Answer:** **0.3**