MISSED THIS? Watch KCV: Atomic Theory; Read Section 2.3. You can click on the Review link to access the section in your eText. An automobile gasoline tank holds 35.0 kg of gasoline. When all of the gasoline burns, 158.0 kg of oxygen is consumed, and carbon dioxide and water are produced. Express your answer to one decimal place with the appropriate units.

To solve this problem, we need to determine the mass of carbon dioxide and water produced when the gasoline burns. We can use the concept of stoichiometry from chemistry, which relates the quantities of reactants and products in a chemical reaction. ### Known Conditions: 1. Mass of gasoline (C) = 35.0 kg 2. Mass of oxygen (O) consumed = 158.0 kg ### Step-by-Step Solution: 1. **Identify the combustion reaction**: The combustion of gasoline (which primarily consists of hydrocarbons) can be represented by a general equation: \[ C_xH_y + O_2 \rightarrow CO_2 + H_2O \] where \(C_xH_y\) represents the hydrocarbon in gasoline. 2. **Determine the products**: When gasoline burns, it produces carbon dioxide (CO₂) and water (H₂O). 3. **Use stoichiometry**: The balanced equation for the combustion of a hydrocarbon can be used to relate the mass of gasoline to the mass of CO₂ and H₂O produced. However, we need to know the specific hydrocarbon composition to get exact ratios. For simplicity, we can assume complete combustion. 4. **Calculate the total mass of products**: According to the law of conservation of mass, the total mass of reactants equals the total mass of products. Therefore, we can express this as: \[ \text{Mass of gasoline} + \text{Mass of oxygen} = \text{Mass of CO}_2 + \text{Mass of H}_2O \] 5. **Let \(m_{CO_2}\) be the mass of carbon dioxide produced and \(m_{H_2O}\) be the mass of water produced**: \[ 35.0 \, \text{kg} + 158.0 \, \text{kg} = m_{CO_2} + m_{H_2O} \] 6. **Calculate the total mass of products**: \[ m_{CO_2} + m_{H_2O} = 193.0 \, \text{kg} \] ### Final Answer: The total mass of carbon dioxide and water produced when the gasoline burns is \(193.0 \, \text{kg}\). Thus, the answer is: \[ \boxed{193.0 \, \text{kg}} \]