\( f(x)=\sqrt{25-x^{2}} \) e \( g(x)=3 \)

Did you know that the function \( f(x) = \sqrt{25 - x^2} \) represents a semicircle? Specifically, it's the upper half of a circle centered at the origin with a radius of 5. This means that for any \( x \) between -5 and 5, \( f(x) \) outputs a non-negative height, which represents the y-coordinate of points on that semicircle! On the other hand, the function \( g(x) = 3 \) is a horizontal line that runs parallel to the x-axis, cutting through all points where y equals 3. To find where these two functions intersect, simply set them equal: \( \sqrt{25 - x^2} = 3 \). Solving this gives an interesting glimpse into where the semicircle and the line cross each other!