Find the degree, leading term, leading coefficient, constant term, and end behavior of the given polynomial. \( p(t)=t^{5}(2-5 t)\left(t^{2}+t+8\right) \) Degree: Leading term: Leading coefficient: End behavior: As \( t \rightarrow-\infty, p(t) \rightarrow \square \) As \( t \rightarrow \infty, p(t) \rightarrow \square \)
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To analyze the polynomial \( p(t) = t^{5}(2-5t)(t^{2}+t+8) \), we can start by expanding it step by step. First, find the degree of each factor: - The first factor \( t^{5} \) has a degree of 5. - The second factor \( (2 - 5t) \) has a degree of 1. - The third factor \( (t^{2} + t + 8) \) has a degree of 2. When finding the overall degree of the polynomial \( p(t) \), we add the degrees together: \[ \text{Degree} = 5 + 1 + 2 = 8. \] Now let's look for the leading term and leading coefficient. The leading term is determined by multiplying the leading terms of each factor: - The leading term from \( t^{5} \) is \( t^{5} \). - The leading term from \( (2 - 5t) \) is \( -5t \). - The leading term from \( (t^{2} + t + 8) \) is \( t^2 \). Thus, the overall leading term is: \[ t^{5} \cdot (-5t) \cdot t^2 = -5t^{8}. \] The leading coefficient, which is the coefficient of the leading term, is \(-5\). The constant term is the value of the polynomial when \( t = 0 \): \[ p(0) = 0^{5}(2 - 5(0))(0^{2} + 0 + 8) = 0. \] Finally, regarding end behavior, a polynomial with an even degree and a negative leading coefficient (like \(-5t^{8}\)) will trend downward on both ends: - As \( t \rightarrow -\infty, p(t) \rightarrow -\infty \) - As \( t \rightarrow \infty, p(t) \rightarrow -\infty \) In summary: Degree: 8 Leading term: \(-5t^{8}\) Leading coefficient: \(-5\) Constant term: 0 As \( t \rightarrow -\infty, p(t) \rightarrow -\infty \) As \( t \rightarrow \infty, p(t) \rightarrow -\infty \)