Use the change of base formula to compute \( \log _{4} 6 \). Round your answer to the nearest thousandth.
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To compute \( \log_{4} 6 \) using the change of base formula, we can use the formula \[ \log_{b}(a) = \frac{\log_{k}(a)}{\log_{k}(b)} \] for any base \( k \). A common choice for \( k \) is 10 or \( e \). Here, let's use base 10: \[ \log_{4} 6 = \frac{\log_{10}(6)}{\log_{10}(4)} \] Now calculating the logarithms: 1. \( \log_{10}(6) \approx 0.7781 \) 2. \( \log_{10}(4) \approx 0.6021 \) Now substituting these values into the formula: \[ \log_{4} 6 \approx \frac{0.7781}{0.6021} \approx 1.292 \] Rounding to the nearest thousandth, we find: \[ \log_{4} 6 \approx 1.292 \]