Of the elements: $$ \mathrm{B}, \mathrm{C}, \mathrm{F}, \mathrm{Li} $$, and Na . The element with the least metallic character is $$ \begin{array}{l}\mathrm{B} . \ \mathrm{F} . \ \mathrm{Na} ext {. }\end{array} $$

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Of the elements: $$ \mathrm{B}, \mathrm{C}, \mathrm{F}, \mathrm{Li} $$, and Na . The element with the least metallic character is $$ \begin{array}{l}\mathrm{B} . \ \mathrm{F} . \ \mathrm{Na} 	ext {. }\end{array} $$

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Among the elements listed—**Boron (B)**, **Carbon (C)**, **Fluorine (F)**, **Lithium (Li)**, and **Sodium (Na)**—we need to identify the one with the **least metallic character**.

**Metallic character** refers to how readily an element can lose electrons to form positive ions. It generally **increases**:
- **Down a group** in the periodic table (as atoms become larger and the outer electrons are farther from the nucleus).
- **From right to left** across a period (as elements transition from nonmetals to metals).

Let's analyze the options provided:

1. **Sodium (Na):** 
   - **Group:** 1 (Alkali metals)
   - **Characteristic:** Highly metallic; readily loses one electron to form Na⁺ ions.

2. **Boron (B):**
   - **Group:** 13
   - **Characteristic:** Metalloid; exhibits both metallic and nonmetallic properties, but still retains some metallic character.

3. **Fluorine (F):**
   - **Group:** 17 (Halogens)
   - **Characteristic:** Highly nonmetallic; the most electronegative element, strongly attracts electrons and does not exhibit metallic properties.

**Conclusion:** **Fluorine (F)** has the **least metallic character** among the given elements.

**Answer:** F Fluorine is the element with the least metallic character among the choices.
Fluorine (F) has the least metallic character among the given elements.

Of the elements: , and Na . The element with the least metallic character is

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