Answer
To solve \( \frac{2}{5} y = 6 \):
1. **Multiplication Property of Equality**:
- Multiply both sides by \( \frac{5}{2} \):
\[
y = 15
\]
2. **Division Property of Equality**:
- Divide both sides by \( \frac{2}{5} \):
\[
y = 15
\]
Both methods give \( y = 15 \).
Solution
To solve the equation \( \frac{2}{5} y = 6 \) using the Multiplication Property of Equality and the Division Property of Equality, we will follow these steps:
### Step 1: Multiplication Property of Equality
The Multiplication Property of Equality states that if you multiply both sides of an equation by the same non-zero number, the two sides remain equal.
1. **Identify the equation**:
\[
\frac{2}{5} y = 6
\]
2. **Multiply both sides by the reciprocal of \( \frac{2}{5} \)**, which is \( \frac{5}{2} \):
\[
\frac{5}{2} \cdot \frac{2}{5} y = \frac{5}{2} \cdot 6
\]
3. **Simplify the left side**:
\[
y = \frac{5}{2} \cdot 6
\]
4. **Calculate \( \frac{5}{2} \cdot 6 \)**:
\[
y = \frac{5 \cdot 6}{2} = \frac{30}{2} = 15
\]
So, using the Multiplication Property of Equality, we find that:
\[
y = 15
\]
### Step 2: Division Property of Equality
The Division Property of Equality states that if you divide both sides of an equation by the same non-zero number, the two sides remain equal.
1. **Start with the original equation**:
\[
\frac{2}{5} y = 6
\]
2. **Divide both sides by \( \frac{2}{5} \)**:
\[
y = 6 \div \frac{2}{5}
\]
3. **Dividing by a fraction is the same as multiplying by its reciprocal**:
\[
y = 6 \cdot \frac{5}{2}
\]
4. **Calculate \( 6 \cdot \frac{5}{2} \)**:
\[
y = \frac{6 \cdot 5}{2} = \frac{30}{2} = 15
\]
So, using the Division Property of Equality, we also find that:
\[
y = 15
\]
### Conclusion
In both methods, we arrive at the same solution: \( y = 15 \). The Multiplication Property of Equality allows us to eliminate the fraction by multiplying, while the Division Property of Equality allows us to isolate \( y \) by dividing by the fraction. Both properties are fundamental in solving equations effectively.
Reviewed and approved by the UpStudy tutoring team
Explain
Simplify this solution