Question
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Q. Activity 19 : Think Deeper!
Solve the following:
  1. The amount of gasoline used by a car varies jointly as the distance travelled and the square
    root of the speed. Suppose a car used 25 liters on a 100 kilometer trip at . About
    how many liters will it use on a 192 kilometer trip at ?
  2. The area of triangle varies jointly as the base and the height. A triangle with a base of 8 cm
    and a height of 9 cm has an area of 36 square centimeters. Find the area when the base is 10 cm
    and the height is 7 cm .
  3. The volume of a right circular cylinder varies jointly as the height and the square of the radius.
    The volume of a right circular cylinder, with radius 4 centimeters and height 7 centimeters ,
    is 112 cm . Find the volume of another cylinder with radius 8 centimeters and height 14
    centimeters.
  4. The mass of a rectangular sheet of wood varies jointly as the length and the width. When
    the length is 20 cm and the width is 10 cm , the mass is 200 grams. Find the mass when the
    length is 15 cm and the width is 10 cm .
  5. The weight of a rectangular block of metal varies jointly as its length, width and thickness.

Ask by Watson Erickson. in the Philippines
Dec 08,2024

Upstudy AI Solution

Tutor-Verified Answer

Answer

  1. The car will use 38.4 liters of gasoline on a 192 km trip at 64 km/hr.
  2. The area of the triangle with a base of 10 cm and a height of 7 cm is 35 cm².
  3. The volume of the cylinder with a radius of 8 cm and a height of 14 cm is 896 cm³.
  4. The mass of the rectangular sheet of wood with a length of 15 cm and a width of 10 cm is 150 grams.

Solution

Let’s solve each of the problems step by step.

Problem 1:

The amount of gasoline used varies jointly as the distance and the square root of the speed . This can be expressed as:
where is the constant of variation.
From the information given:
  • liters
  • km
  • km/hr
Substituting these values into the equation:
Now, we need to find the gasoline used for a trip of km at km/hr:

Problem 2:

The area of a triangle varies jointly as the base and the height :
From the information given:
  • cm²
  • cm
  • cm
Substituting these values:
Now, we need to find the area when cm and cm:
²

Problem 3:

The volume of a right circular cylinder varies jointly as the height and the square of the radius :
From the information given:
  • cm³
  • cm
  • cm
Substituting these values:
Now, we need to find the volume for cm and cm:
³

Problem 4:

The mass of a rectangular sheet of wood varies jointly as the length and the width :
From the information given:
  • grams
  • cm
  • cm
Substituting these values:
Now, we need to find the mass when cm and cm:

Problem 5:

The weight of a rectangular block of metal varies jointly as its length , width , and thickness :
To solve this problem, we would need specific values for the dimensions and the weight of the block to find the constant and then calculate the weight for another set of dimensions. If you provide those values, I can help you with that calculation!

Answered by UpStudy AI and reviewed by a Professional Tutor

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Beyond the Answer

  1. To solve the gasoline problem, we start with the formula . Using the first scenario, we find where , , and . This gives us . Now, for the second trip with and , plug those values into the equation: , yielding approximately liters used.
  2. For the triangle’s area, we use the formula . With the given parameters, , we can confirm our formula works. To find the new area with cm and cm, we calculate , which results in an area of square centimeters.
  3. The volume of the cylinder is calculated with . For the first cylinder, substituting values gives us , solving for . Now for the second cylinder with radius cm and height cm, we compute , resulting in a volume of cubic centimeters.
  4. The mass of the wood can be expressed with the formula . Using the initial information, , we find . For the new length of cm and width of cm, the mass calculates to , which is grams.
  5. To determine the weight of a rectangular block of metal, you’ll use the formula , where , , and represent the block’s length, width, and thickness respectively. Always remember to find from an example scenario to apply it to new dimensions!

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