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When \( b = 5 \), \( 2b^{2} + 4 = 54 \).
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To solve the expression \( 2b^{2} + 4 \) when \( b = 5 \), we first substitute \( b \) with 5. This gives us \( 2(5)^{2} + 4 \). Now, calculate \( (5)^{2} = 25 \). Then, multiply by 2: \( 2 \times 25 = 50 \). Finally, add 4: \( 50 + 4 = 54 \). So, the value of \( 2b^{2} + 4 \) when \( b = 5 \) is 54.
