Graph the line. $$ -2 x+y=-8 $$

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To graph the line given by the equation $$-2x + y = -8$$, we can first rewrite it in slope-intercept form, $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept.

Starting with the original equation:

$$
-2x + y = -8
$$

We can isolate $$y$$ by adding $$2x$$ to both sides:

$$
y = 2x - 8
$$

Now, we can identify the slope and y-intercept from this equation:

- The slope $$m$$ is $$2$$.
- The y-intercept $$b$$ is $$-8$$.

This means the line crosses the y-axis at the point $$(0, -8)$$.

Next, we can find another point on the line by choosing a value for $$x$$. Let's choose $$x = 1$$:

$$
y = 2(1) - 8 = 2 - 8 = -6
$$

So, another point on the line is $$(1, -6)$$.

Now we have two points: $$(0, -8)$$ and $$(1, -6)$$. We can plot these points on a graph and draw a line through them.

1. Plot the point $$(0, -8)$$ on the y-axis.
2. Plot the point $$(1, -6)$$.
3. Draw a straight line through these points, extending it in both directions.

The graph of the line $$-2x + y = -8$$ will look like this:

- The line will rise as it moves from left to right, reflecting the positive slope of $$2$$.
- The y-intercept is at $$(0, -8)$$, and the line passes through $$(1, -6)$$.

If you were to graph it on a coordinate plane, it would look like this:

```
y
|
|          *
|        *
|      *
|    *
|  *
|*
|____________________ x
```

The line continues infinitely in both directions.
The line $$-2x + y = -8$$ has a slope of $$2$$ and a y-intercept at $$(0, -8)$$. Plot the points $$(0, -8)$$ and $$(1, -6)$$ and draw a line through them.

Graph the line. \[ -2 x+y=-8 \]

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