Questions A. Rationalise the denominators of the following expressions: \( \begin{array}{ll}\text { 3. } \frac{2}{4+\sqrt{2}} & \text { 4. } \frac{6}{3-\sqrt{5}}\end{array} \)
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To rationalise the denominator of \( \frac{2}{4+\sqrt{2}} \), multiply the numerator and denominator by the conjugate \( 4-\sqrt{2} \). This gives you \( \frac{2(4-\sqrt{2})}{(4+\sqrt{2})(4-\sqrt{2})} = \frac{8 - 2\sqrt{2}}{16 - 2} = \frac{8 - 2\sqrt{2}}{14} = \frac{4 - \sqrt{2}}{7} \). For \( \frac{6}{3-\sqrt{5}} \), also multiply the numerator and denominator by the conjugate \( 3+\sqrt{5} \). This results in \( \frac{6(3+\sqrt{5})}{(3-\sqrt{5})(3+\sqrt{5})} = \frac{18 + 6\sqrt{5}}{9 - 5} = \frac{18 + 6\sqrt{5}}{4} = \frac{9 + 3\sqrt{5}}{2} \).