Question
Factor the difference of squares: \( 16a^{4} - b^{2} \)
Ask by Willis Osborne. in South Africa
Jan 12,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( 16a^{4} - b^{2} = (4a^{2} + b)(4a^{2} - b) \)
Solution
To factor the expression \( 16a^{4} - b^{2} \) as a difference of squares, follow these steps:
### Step 1: Identify the Perfect Squares
First, recognize that both terms in the expression are perfect squares:
- \( 16a^{4} \) can be written as \( (4a^{2})^{2} \)
- \( b^{2} \) is already a perfect square
### Step 2: Apply the Difference of Squares Formula
The difference of squares formula is:
\[
A^{2} - B^{2} = (A + B)(A - B)
\]
Apply this formula to the expression:
\[
16a^{4} - b^{2} = (4a^{2})^{2} - (b)^{2} = (4a^{2} + b)(4a^{2} - b)
\]
### Step 3: Check for Further Factoring
Examine each factor to see if it can be factored further:
1. **\( 4a^{2} + b \):** This is a sum of squares, which cannot be factored further using real numbers.
2. **\( 4a^{2} - b \):** This is a difference of squares only if \( b \) is a perfect square. Since \( b \) is a variable and not necessarily a square term, it cannot be factored further in general.
### Final Factored Form
\[
16a^{4} - b^{2} = (4a^{2} + b)(4a^{2} - b)
\]
This is the fully factored form of the given expression.
Reviewed and approved by the UpStudy tutoring team
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Bonus Knowledge
To factor the difference of squares \( 16a^{4} - b^{2} \), you can use the formula \( A^2 - B^2 = (A - B)(A + B) \). Here, you can identify \( A = 4a^{2} \) (since \( (4a^{2})^2 = 16a^{4} \)) and \( B = b \) (since \( b^2 = b^2 \)). So, the expression can be factored as follows: \[ 16a^{4} - b^{2} = (4a^{2} - b)(4a^{2} + b) \] And there you have it! The difference of squares is elegantly factored!