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Problem 1 Answer the following questions and graph the function \( y=2 \cos (x-\pi) \) - Amplitude: \( \qquad \) - Period: \( \qquad \) and Xscale: \( \qquad \) - Vertical Shift: \( \qquad \) Horizontal Shift \( \qquad \) - Starting point \( \qquad \) and Ending Point \( \qquad \)

Ask by Wang Gonzalez. in the United States
Jan 27,2025

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Answer

- **Amplitude:** 2 - **Period:** \( 2\pi \) - **X-scale:** 1 - **Vertical Shift:** 0 - **Horizontal Shift:** \( \pi \) - **Starting Point:** \( \pi \) - **Ending Point:** \( 3\pi \)

Solution

Certainly! Let's analyze and graph the function \( y = 2 \cos (x - \pi) \) by answering each of the provided questions. ### Function Analysis The given function is in the form: \[ y = A \cos(B(x - C)) + D \] where: - \( A \) = Amplitude - \( B \) affects the period (\( \text{Period} = \frac{2\pi}{B} \)) - \( C \) = Horizontal Shift - \( D \) = Vertical Shift For \( y = 2 \cos (x - \pi) \): - \( A = 2 \) - \( B = 1 \) - \( C = \pi \) - \( D = 0 \) ### Answers - **Amplitude:** \( \boxed{2} \) - **Period:** \( \boxed{2\pi} \) **X-scale:** \( \boxed{1} \) (Since \( B = 1 \), there's no horizontal scaling applied.) - **Vertical Shift:** \( \boxed{0} \) **Horizontal Shift:** \( \boxed{\pi} \) (The graph is shifted \( \pi \) units to the right.) - **Starting Point:** \( \boxed{\pi} \) **Ending Point:** \( \boxed{3\pi} \) (One complete cycle starts at \( x = \pi \) and ends at \( x = 3\pi \).) ### Graph of \( y = 2 \cos (x - \pi) \) Below is a sketch of the graph over one period: ``` y | 2 | * * | * * * * | * * * * 0 |----*-----------*-------*-----------*---- x | * * * * -2| * * * * | * * | ``` **Key Features:** - **Amplitude:** The graph oscillates between \( y = 2 \) and \( y = -2 \). - **Period:** One complete cycle from \( x = \pi \) to \( x = 3\pi \). - **Horizontal Shift:** The standard cosine graph \( y = \cos(x) \) is shifted \( \pi \) units to the right. - **Vertical Shift:** There is no vertical shift; the center line is at \( y = 0 \). - **Starting Point:** The maximum point starts at \( x = \pi \), \( y = 2 \). - **Ending Point:** The graph returns to the maximum point at \( x = 3\pi \), \( y = 2 \). ### Summary | Feature | Value | |-------------------|--------------| | **Amplitude** | 2 | | **Period** | \( 2\pi \) | | **X-scale** | 1 | | **Vertical Shift**| 0 | | **Horizontal Shift**| \( \pi \) | | **Starting Point**| \( \pi \) | | **Ending Point** | \( 3\pi \) | Feel free to plot these points and features on a coordinate plane to visualize the graph accurately!

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For the function \( y = 2 \cos(x - \pi) \): - Amplitude: The amplitude is the coefficient of the cosine function, which is \( 2 \). This means the function will oscillate between \( 2 \) and \( -2 \). - Period: The standard period of the cosine function is \( 2\pi \). Since there’s no horizontal scaling factor, the period remains \( 2\pi \). Xscale can be considered \( \frac{2\pi}{4} = \frac{\pi}{2} \) if you're charting on a typical 4x unit system. - Vertical Shift: There’s no vertical shift in this function, so it is \( 0 \). Horizontal Shift: The expression \( (x - \pi) \) indicates a horizontal shift of \( \pi \) units to the right. - Starting point: At \( x = \pi \), the cosine function starts at its maximum value, so the starting point is \( (\pi, 2) \). - Ending Point: To find the ending point, we can determine where the function has completed one full cycle. The function returns to its original position at \( x = \pi + 2\pi = 3\pi \), which gives us the ending point \( (3\pi, 2) \). So, when you graph \( y = 2 \cos(x - \pi) \), plot the specified points and use the identified features to create a wave that oscillates between \( 2 \) and \( -2 \) over intervals defined by the period!

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