Question
The following equation involves more than one exponential expression. Solve the equation. \[ 12^{x}=4^{x+2} \]
Ask by Franklin Carrillo. in the United States
Oct 28,2024
Real Tutor Solution
Tutor-Verified Answer
Answer
\( x=\frac{4}{\log_{2}{(3)}} \)
Solution
Solve the equation \( 12^{x}=4^{x+2} \).
Solve the equation by following steps:
- step0: Solve for \(x\):
\(12^{x}=4^{x+2}\)
- step1: Take the logarithm of both sides:
\(\log_{4}{\left(12^{x}\right)}=\log_{4}{\left(4^{x+2}\right)}\)
- step2: Evaluate the logarithm:
\(\frac{x}{2}\log_{2}{\left(12\right)}=\frac{2\left(x+2\right)}{2}\)
- step3: Rewrite the expression:
\(\frac{x\log_{2}{\left(12\right)}}{2}=\frac{2\left(x+2\right)}{2}\)
- step4: Multiply both sides of the equation by LCD:
\(\frac{x\log_{2}{\left(12\right)}}{2}\times 2=\frac{2\left(x+2\right)}{2}\times 2\)
- step5: Simplify the equation:
\(\log_{2}{\left(12\right)}\times x=2x+4\)
- step6: Move the variable to the left side:
\(\log_{2}{\left(12\right)}\times x-2x=4\)
- step7: Collect like terms:
\(\left(\log_{2}{\left(12\right)}-2\right)x=4\)
- step8: Divide both sides:
\(\frac{\left(\log_{2}{\left(12\right)}-2\right)x}{\log_{2}{\left(12\right)}-2}=\frac{4}{\log_{2}{\left(12\right)}-2}\)
- step9: Divide the numbers:
\(x=\frac{4}{\log_{2}{\left(12\right)}-2}\)
- step10: Simplify:
\(x=\frac{4}{\log_{2}{\left(3\right)}}\)
The solution to the equation \(12^{x}=4^{x+2}\) is \(x=\frac{4}{\log_{2}{(3)}}\).
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