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Choose all of the equations below that have only one solution for \( x \) when \[ 0^{\circ} \leq x \leq 360^{\circ} \] \[ \begin{array}{llll}\sin x=-1 & \sin x=0 & \sin x=0.5 & \sin x=1 \\ \cos x=-1 & \cos x=0 & \cos x=0.5 & \cos x=1\end{array} \]

Ask by Evans Watson. in the United Kingdom
Nov 23,2024

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The equations with only one solution are: \(\sin x = -1\), \(\sin x = 1\), \(\cos x = -1\).

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Beyond the Answer

The equations with only one solution for \( x \) within the range \( 0^{\circ} \leq x \leq 360^{\circ} \) are: 1. \( \sin x = -1 \) has a unique solution at \( x = 270^{\circ} \). 2. \( \cos x = -1 \) has a unique solution at \( x = 180^{\circ} \). All the other equations listed have more than one solution in this interval. For instance, \( \sin x = 0 \) has solutions at \( 0^{\circ}, 180^{\circ}, \) and \( 360^{\circ} \), while \( \sin x = 0.5 \) has solutions at \( 30^{\circ} \) and \( 150^{\circ} \). Similarly, \( \cos x = 0 \) has solutions at \( 90^{\circ} \) and \( 270^{\circ} \), and \( \cos x = 0.5 \) has solutions at \( 60^{\circ} \) and \( 300^{\circ} \).

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