Use the order of operations to simplify the expression. \( 6+\frac{3^{2}}{5-2}-(-7) \) \( 6+\frac{3^{2}}{5-2}-(-7)=\square \)

To simplify the expression \( 6+\frac{3^{2}}{5-2}-(-7) \), we start with the order of operations (PEMDAS/BODMAS). First, we handle the exponent: \( 3^2 = 9 \). Next, we evaluate the denominator: \( 5 - 2 = 3 \). Then, we substitute these values back into the expression: \[ 6 + \frac{9}{3} - (-7) \] Now, we simplify \( \frac{9}{3} = 3 \). This gives us: \[ 6 + 3 - (-7) \] Since subtracting a negative is the same as adding a positive, this becomes: \[ 6 + 3 + 7 \] Finally, we add these together: \[ 6 + 3 = 9 \quad \text{then} \quad 9 + 7 = 16 \] Thus, the simplified expression is: \( 6+\frac{3^{2}}{5-2}-(-7)=16 \)