Question
upstudy study bank question image url

Simplify the algebraic expression. \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}} \) \( \frac{x^{2}-2 x y+y^{2}}{x}=\square \)

Ask by Williams Summers. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{(x - y)yx}{x + y} = \square \]

Solution

Simplify the expression by following steps: - step0: : \(x^{2}-2xy+y^{2}\) Expand the expression \( \frac{x}{y}-\frac{y}{x} \) Simplify the expression by following steps: - step0: Subtract the terms: \(\frac{x}{y}-\frac{y}{x}\) - step1: Reduce fractions to a common denominator: \(\frac{x\times x}{yx}-\frac{y\times y}{xy}\) - step2: Rewrite the expression: \(\frac{x\times x}{yx}-\frac{y\times y}{yx}\) - step3: Transform the expression: \(\frac{x\times x-y\times y}{yx}\) - step4: Multiply the terms: \(\frac{x^{2}-y\times y}{yx}\) - step5: Multiply the terms: \(\frac{x^{2}-y^{2}}{yx}\) Expand the expression \( \frac{x^{2}-2xy+y^{2}}{\frac{x^{2}-y^{2}}{yx}} \) Simplify the expression by following steps: - step0: Multiply the terms: \(\frac{x^{2}-2xy+y^{2}}{\frac{x^{2}-y^{2}}{yx}}\) - step1: Multiply by the reciprocal: \(\left(x^{2}-2xy+y^{2}\right)\times \frac{yx}{x^{2}-y^{2}}\) - step2: Rewrite the expression: \(\left(x-y\right)^{2}\times \frac{yx}{\left(x-y\right)\left(x+y\right)}\) - step3: Reduce the fraction: \(\left(x-y\right)\times \frac{yx}{x+y}\) - step4: Multiply the terms: \(\frac{\left(x-y\right)yx}{x+y}\) - step5: Multiply the terms: \(\frac{yx\left(x-y\right)}{x+y}\) - step6: Multiply the terms: \(\frac{yx^{2}-y^{2}x}{x+y}\) To simplify the algebraic expression \[ \frac{x^{2}-2xy+y^{2}}{\frac{x}{y}-\frac{y}{x}}, \] we will follow these steps: 1. **Simplify the numerator**: The numerator is \(x^{2} - 2xy + y^{2}\). This expression can be recognized as a perfect square trinomial, which factors to: \[ (x - y)^{2}. \] 2. **Simplify the denominator**: The denominator is \(\frac{x}{y} - \frac{y}{x}\). To combine these fractions, we find a common denominator: \[ \frac{x^{2} - y^{2}}{yx}. \] 3. **Combine the simplified numerator and denominator**: Now we can rewrite the original expression as: \[ \frac{(x - y)^{2}}{\frac{x^{2} - y^{2}}{yx}}. \] 4. **Simplify the overall expression**: Dividing by a fraction is equivalent to multiplying by its reciprocal: \[ \frac{(x - y)^{2} \cdot yx}{x^{2} - y^{2}}. \] 5. **Recognize that \(x^{2} - y^{2}\) can be factored**: The expression \(x^{2} - y^{2}\) can be factored as \((x - y)(x + y)\). Thus, we have: \[ \frac{(x - y)^{2} \cdot yx}{(x - y)(x + y)}. \] 6. **Cancel common factors**: We can cancel one \((x - y)\) from the numerator and denominator: \[ \frac{(x - y) \cdot yx}{x + y}. \] Thus, the simplified expression is: \[ \frac{(x - y)yx}{x + y}. \] So, the final answer is: \[ \frac{(x - y)yx}{x + y} = \square. \]

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

The Deep Dive

To simplify the expression \( \frac{x^{2}-2xy+y^{2}}{\frac{x}{y}-\frac{y}{x}} \), let's first simplify the denominator: \[ \frac{x}{y} - \frac{y}{x} = \frac{x^2 - y^2}{xy} \] Now, substituting this back into the expression, we have: \[ \frac{x^2 - 2xy + y^2}{\frac{x^2 - y^2}{xy}} = \frac{(x^2 - 2xy + y^2) \cdot (xy)}{x^2 - y^2} \] Next, notice that \( x^2 - 2xy + y^2 = (x - y)^2 \) and \( x^2 - y^2 = (x - y)(x + y) \). Thus, our expression becomes: \[ \frac{(x - y)^2 \cdot (xy)}{(x - y)(x + y)} = \frac{(x - y) \cdot (xy)}{x + y} \] Now, we can conclude that: \[ \frac{x^2-2xy+y^2}{\frac{x}{y}-\frac{y}{x}} = \frac{(x-y) \cdot xy}{x+y} \] So, the final simplified expression is \( \frac{(x - y) \cdot xy}{x + y} \). Additionally, when \( x = y \), the original expression becomes undefined due to division by zero in the denominator. Always check for such cases to avoid errors!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy