Find an equation of the inverse relation. \( y=5 x+7 \) A. \( y=\frac{x}{5}-7 \) B. \( x=5 y-7 \) C. \( x=5 y+7 \) D. \( x=\frac{y+7}{5} \)

To find the inverse relation of the given equation \( y = 5x + 7 \), first, we need to swap \( x \) and \( y \) to start the process, resulting in \( x = 5y + 7 \). Next, we solve for \( y \) by isolating it on one side, which gives us \( y = \frac{x - 7}{5} \). Therefore, by rearranging, the equation of the inverse relation is \( x = 5y - 7 \), which matches option B. Therefore, the answer is: B. \( x = 5y - 7 \)