QUESTION 2 (12 marks)
A single-story factory has a 1.5 MVA, 22kVIASV, ONAN, DYN11 distribution transformer
to provide electricity for the factory.
(i) Calculate the current supplying to the factory

Question

QUESTION 2 (12 marks) A single-story factory has a 1.5 MVA, 22kVIASV, ONAN, DYN11 distribution transformer to provide electricity for the factory. (i) Calculate the current supplying to the factory

UpStudy AI · Accepted Answer

To calculate the current supplied by the transformer to the factory, we can use the formula for three-phase power:

$$
P = \sqrt{3} \times V \times I
$$

Where:
- $$ P $$ is the power in watts (W)
- $$ V $$ is the line-to-line voltage in volts (V)
- $$ I $$ is the current in amperes (A)

Given:
- The power rating of the transformer $$ P = 1.5 \, \text{MVA} = 1.5 \times 10^6 \, \text{VA} $$
- The line-to-line voltage $$ V = 22 \, \text{kV} = 22 \times 10^3 \, \text{V} $$

We can rearrange the formula to solve for current $$ I $$:

$$
I = \frac{P}{\sqrt{3} \times V}
$$

Now, substituting the values:

$$
I = \frac{1.5 \times 10^6}{\sqrt{3} \times 22 \times 10^3}
$$

Calculating $$ \sqrt{3} $$:

$$
\sqrt{3} \approx 1.732
$$

Now substituting this value into the equation:

$$
I = \frac{1.5 \times 10^6}{1.732 \times 22 \times 10^3}
$$

Calculating the denominator:

$$
1.732 \times 22 \times 10^3 \approx 38,184
$$

Now substituting this back into the equation for current:

$$
I = \frac{1.5 \times 10^6}{38,184} \approx 39.2 \, \text{A}
$$

Thus, the current supplying to the factory is approximately **39.2 A**.
The current supplied to the factory is approximately 39.2 A.

QUESTION 2 (12 marks)
A single-story factory has a 1.5 MVA, 22kVIASV, ONAN, DYN11 distribution transformer
to provide electricity for the factory.
(i) Calculate the current supplying to the factory

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