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Find the DOMAIN and RANGE of th 15. \( y=2 x-1 \) \( y=\sqrt{x-7} \)

Ask by Gough Salinas. in the Philippines
Jan 20,2025

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**Domain and Range:** 1. **\( y = 2x - 1 \)** - **Domain:** All real numbers (\( -\infty \) to \( \infty \)) - **Range:** All real numbers (\( -\infty \) to \( \infty \)) 2. **\( y = \sqrt{x - 7} \)** - **Domain:** \( x \geq 7 \) (\( [7, \infty) \)) - **Range:** \( y \geq 0 \) (\( [0, \infty) \))

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The Deep Dive

For the function \( y = 2x - 1 \), the domain is all real numbers since you can substitute any value for \( x \). The range is also all real numbers, as for any \( y \) value, you can find an \( x \) that satisfies the equation. For the function \( y = \sqrt{x-7} \), the domain is \( x \geq 7 \) because you need the expression inside the square root to be non-negative. The range starts from 0 (when \( x = 7 \)) and goes up to infinity, so the range is \( y \geq 0 \).

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