40. The price of a raincoat was slashed from Rs. 1060 to Rs .901 by a shopkeeper in the rainy season to boost the sales. Find the rate of discount given by him. 41. By repeated subtraction method, verify the result: 320,120 and 95

Let's solve both problems step by step. --- ### **Problem 40** **The price of a raincoat was slashed from Rs. 1060 to Rs. 901 by a shopkeeper in the rainy season to boost sales. Find the rate of discount given by him.** **Solution:** 1. **Calculate the Discount Amount:** \[ \text{Discount} = \text{Original Price} - \text{Selling Price} = 1060 - 901 = 159 \text{ Rs.} \] 2. **Calculate the Rate of Discount:** \[ \text{Rate of Discount} = \left( \frac{\text{Discount}}{\text{Original Price}} \right) \times 100 = \left( \frac{159}{1060} \right) \times 100 \] \[ \text{Rate of Discount} \approx 15\% \] **Answer:** The rate of discount given was **15%**. --- ### **Problem 41** **By repeated subtraction method, verify the result: GCD of 320, 120, and 95.** **Solution:** To find the Greatest Common Divisor (GCD) of multiple numbers using the repeated subtraction method, we can find the GCD of two numbers first and then find the GCD of the result with the next number. 1. **Find GCD of 320 and 120:** - \(320 - 120 = 200\) - \(200 - 120 = 80\) - \(120 - 80 = 40\) - \(80 - 40 = 40\) - \(40 - 40 = 0\) **GCD of 320 and 120 is 40.** 2. **Find GCD of 40 and 95:** - \(95 - 40 = 55\) - \(55 - 40 = 15\) - \(40 - 15 = 25\) - \(25 - 15 = 10\) - \(15 - 10 = 5\) - \(10 - 5 = 5\) - \(5 - 5 = 0\) **GCD of 40 and 95 is 5.** **Final Answer:** The GCD of 320, 120, and 95 is **5**. --- **Summary:** - **Problem 40 Answer:** 15% discount. - **Problem 41 Answer:** GCD is 5.