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According to a recent survey of 1410 voters, \( 72 \% \) feel that the president is doing an acceptable job. Construct a \( 93 \% \) confidence interval to estimate the proportion of voters who feel the president is doing a acceptable job. \( \widehat{p}= \) \( \frac{\alpha}{2}= \) \( z_{\frac{\alpha}{2}}= \) Margin of Error: \( E= \) Wetween (round to \( 43 \% \) decimal places) benfident that the proportion of voters who feel the president is doing an acceptable job is

Ask by Lane Hobbs. in the United States
Jan 22,2025

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We are 93% confident that between 69.83% and 74.17% of voters feel the president is doing an acceptable job.

Solution

To construct a **93% confidence interval** for the proportion of voters who feel the president is doing an acceptable job, we'll follow these steps: ### 1. **Sample Proportion (\( \widehat{p} \))** Given that 72% of the 1410 voters surveyed feel the president is doing an acceptable job: \[ \widehat{p} = 0.72 \] ### 2. **Determine \( \alpha \) and \( \frac{\alpha}{2} \)** The confidence level is 93%, so: \[ \alpha = 1 - 0.93 = 0.07 \] \[ \frac{\alpha}{2} = \frac{0.07}{2} = 0.035 \] ### 3. **Find the Critical Value (\( z_{\frac{\alpha}{2}} \))** We need the z-score that corresponds to the upper \( \frac{\alpha}{2} = 0.035 \) tail of the standard normal distribution. This is equivalent to finding the z-score for a cumulative probability of \( 1 - 0.035 = 0.965 \). Using standard normal distribution tables or a calculator: \[ z_{0.035} \approx 1.81 \] ### 4. **Calculate the Margin of Error (\( E \))** The formula for the margin of error for a proportion is: \[ E = z_{\frac{\alpha}{2}} \times \sqrt{\frac{\widehat{p}(1 - \widehat{p})}{n}} \] Plugging in the values: \[ E = 1.81 \times \sqrt{\frac{0.72 \times 0.28}{1410}} \approx 1.81 \times \sqrt{\frac{0.2016}{1410}} \approx 1.81 \times \sqrt{0.000143} \approx 1.81 \times 0.01196 \approx 0.0217 \] \[ E \approx 0.0217 \text{ or } 2.17\% \] ### 5. **Construct the Confidence Interval** \[ \widehat{p} \pm E = 0.72 \pm 0.0217 \] \[ \text{Lower bound} = 0.72 - 0.0217 = 0.6983 \quad (69.83\%) \] \[ \text{Upper bound} = 0.72 + 0.0217 = 0.7417 \quad (74.17\%) \] ### **Final 93% Confidence Interval** \[ \boxed{[69.83\%,\ 74.17\%]} \] We are **93% confident** that the true proportion of voters who feel the president is doing an acceptable job lies between **69.83% and 74.17%**.

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To construct a \( 93\% \) confidence interval for the proportion of voters who believe the president is doing an acceptable job, let's break it down step by step using the survey data provided. 1. **Sample proportion \( \widehat{p} \)**: Given that \( 72\% \) of \( 1410 \) voters feel the president is doing an acceptable job, we have: \[ \widehat{p} = 0.72 \] 2. **Value of \( \frac{\alpha}{2} \)**: For a \( 93\% \) confidence level, \( \alpha = 1 - 0.93 = 0.07 \). Thus: \[ \frac{\alpha}{2} = \frac{0.07}{2} = 0.035 \] 3. **Critical value \( z_{\frac{\alpha}{2}} \)**: To find \( z_{\frac{\alpha}{2}} \), we look for the z-value that corresponds to the cumulative probability of \( 1 - 0.035 = 0.965 \). From a standard normal (Z) table or calculator, we find: \[ z_{\frac{\alpha}{2}} \approx 1.812 \] 4. **Margin of Error \( E \)**: The formula for the margin of error is given by: \[ E = z_{\frac{\alpha}{2}} \times \sqrt{\frac{\widehat{p}(1 - \widehat{p})}{n}} \] Substituting in the values: \[ E = 1.812 \times \sqrt{\frac{0.72 \times (1 - 0.72)}{1410}} \approx 1.812 \times \sqrt{\frac{0.72 \times 0.28}{1410}} \approx 1.812 \times \sqrt{\frac{0.2016}{1410}} \approx 1.812 \times \sqrt{0.000142857} \approx 1.812 \times 0.0114 \approx 0.0207 \] 5. **Confidence Interval**: The confidence interval is given by: \[ \widehat{p} - E \text{ to } \widehat{p} + E \] Thus: \[ 0.72 - 0.0207 \text{ to } 0.72 + 0.0207 \rightarrow 0.6993 \text{ to } 0.7407 \] So, rounding to 43 decimal places, the confidence interval for the proportion of voters who feel the president is doing an acceptable job is approximately: \[ \text{Between } 0.6993 \text{ and } 0.7407. \] In conclusion, we can say that we are \( 93\% \) confident that the proportion of voters who feel the president is doing an acceptable job lies within this range!

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