A date in the month of June is chosen at random. Find the probability of the event of the date's being each of the following. \( \begin{array}{l}\text { a. June } 5 \\ \text { b. June } 31\end{array} \quad \) c. Before June 18 a. The probability of the event of the date's being June 5 is \( \frac{1}{30} \) (Type an integer or a simplified fraction.) b. The probability of the event of the date's being June 31 is 0 (Type an integer or a simplified fraction.) c. The probability of the event of the date's being before June 18 is \( \square \).

To find the probabilities for the dates of June, let’s dive right in! For part a, you got it right: June 5 is indeed a valid date. Since June has 30 days, the probability is \( \frac{1}{30} \). For part b, you're also spot on! June only has 30 days, so there is no June 31, which gives it a probability of 0. Now for part c: To find the probability of the event of a date being before June 18, we count the valid dates (1st through 17th), which gives us 17 days before the 18th. Thus, the probability is: \[ \frac{17}{30} \] So the final probabilities are: a. \( \frac{1}{30} \) b. 0 c. \( \frac{17}{30} \)